def prem(s,nx = [])
  return nx.join if s.empty?
  s.collect { |b| prem(s-[b],nx+[b]) }.flatten
...

Ruby Erlang Riddle for Rubists

by dorkalev, June 13, 2009 06:59, 3 refactorings, tagged with ruby, erlang, permutations

Originally published at htt...