alphanumerics = [*('0'..'9')] + [*('A'..'Z')] + [*('a'..'z')]
(0...25).map { alphanumerics[Kernel.rand(alphanumerics.size)] }.join
alphanumerics = [('0'..'9'),('A'..'Z'),('a'..'z')].map {|range| range.to_a}.flatten
(0...25).map { alphanumerics[Kernel.rand(alphanumerics.size)] }.join
alphanumerics = ('0'..'9').to_a + ('A'..'Z').to_a + ('a'..'z').to_a
(0...25).map { alphanumerics[Kernel.rand(alphanumerics.size)] }.join
Refactorings
No refactoring yet !
VitalieL
July 3, 2008, July 03, 2008 07:47, permalink
No rating.
Login to rate!
You will need to filter numbers from [58-64] to avoid \,~ chars
irb(main):009:0> a = '-'*25
=> "-------------------------"
irb(main):010:0> 25.times {|x| a[x] = rand(90) + 48}
=> 25
irb(main):011:0> a
=> ">Ne~r4[3Skd2\201s6<\\THOD}QYn"
irb(main):012:0>
Ryan Bates
July 3, 2008, July 03, 2008 16:02, permalink
2 ratings.
Login to rate!
In the past I've added a random_string method to the String class which can take a length and array of chars to use. I wouldn't say it's much of an improvement, but some might find it helpful.
class String
def self.random_string(length = 8, chars = nil)
chars ||= ('a'..'z').to_a + ('A'..'Z').to_a + ('0'..'9').to_a
Array.new(length) { chars[rand(chars.size)] }.join
end
end
Raghu Srinivasan
July 6, 2008, July 06, 2008 19:46, permalink
No rating.
Login to rate!
Here's what I've been using as a library function
def random_string(length)
chars = ("a".."z").to_a + ("0".."9").to_a
randomstring = ""
1.upto(length) { |i| randomstring << chars[rand(chars.size-1)] }
end
So this is kind of trivial but I can't help but think there is a better way. I've included a couple different ways.