M = [["a", "b"], ["c", "d"], ["e", "f"]] x = [] M.each do |m| x.push(m[0]) end
Refactorings
No refactoring yet !
Alec Leitner
January 26, 2012, January 26, 2012 08:30, permalink
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M.map(&:first)
x should be ["a","c","e"] in the end. I'm looking for a one-liner, something similar to (Python's) x = [m[0] for m in M]