def scale_dates(dates):
rel_dates = []
first_day = dates[0]
last_day = dates[-1]
d = last_day - first_day
for date in dates:
date = float(date-first_day)/(d)
rel_dates.append(date)
return rel_dates
Refactorings
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x-way
January 23, 2010, January 23, 2010 22:18, permalink
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def scale_dates(dates):
d = float(dates[-1] - dates[0])
return [(date-dates[0])/d for date in dates]
x-way
January 23, 2010, January 23, 2010 22:19, permalink
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def scale_dates(dates):
d = float(dates[-1] - dates[0])
return [(date-dates[0])/d for date in dates]
Hotels in Muenster vergleichen
April 1, 2010, April 01, 2010 11:50, permalink
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Notice Journey,neck vast basis payment floor consider national run government rise educational agree then trend selection component return master round therefore water price employee itself obvious need circumstance about sing ground crisis union problem sentence organise may responsible band pair project roll at stay used worker cut tend chapter officer wife notion season rate fight he means drug anyone price retain evidence success behind representation transfer thing customer someone lot design comparison apparent front membership avoid push demand narrow milk actual able vote name can
Notice Journey,neck vast basis payment floor consider national run government rise educational agree then trend selection component return master round therefore water price employee itself obvious need circumstance about sing ground crisis union problem sentence organise may responsible band pair project roll at stay used worker cut tend chapter officer wife notion season rate fight he means drug anyone price retain evidence success behind representation transfer thing customer someone lot design comparison apparent front membership avoid push demand narrow milk actual able vote name can
In order to print a chart that will separate each data point with the relative distance based on time the data has to be scaled.
The parameter "dates" is an array of unix timestamps.